(7xy^2+x^2-3x^2y)-(4x^2y-2y+5x^2)=0

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Solution for (7xy^2+x^2-3x^2y)-(4x^2y-2y+5x^2)=0 equation: 


Simplifying
(7xy2 + x2 + -3x2y) + -1(4x2y + -2y + 5x2) = 0

Remove parenthesis around (7xy2 + x2 + -3x2y)
7xy2 + x2 + -3x2y + -1(4x2y + -2y + 5x2) = 0

Reorder the terms:
7xy2 + x2 + -3x2y + -1(5x2 + 4x2y + -2y) = 0
7xy2 + x2 + -3x2y + (5x2 * -1 + 4x2y * -1 + -2y * -1) = 0
7xy2 + x2 + -3x2y + (-5x2 + -4x2y + 2y) = 0

Reorder the terms:
7xy2 + x2 + -5x2 + -3x2y + -4x2y + 2y = 0

Combine like terms: x2 + -5x2 = -4x2
7xy2 + -4x2 + -3x2y + -4x2y + 2y = 0

Combine like terms: -3x2y + -4x2y = -7x2y
7xy2 + -4x2 + -7x2y + 2y = 0

Solving
7xy2 + -4x2 + -7x2y + 2y = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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